Question

9. In a triangle ABC, angle A = 90° and D is the mid-point of AC. The value of BC-
BDP is equal to
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Answer 1

Step-by-step explanation:

Just visualize a triangle..

Whose one angle is 90°

Now name sides

A, B, C

D is mid pt of AC

Joint BD

So in triangle BDC,

by Pythagores theorem,

BC^2 = CD^2 + BD^2

BC^2 - BD^2 = CD^2

Answer 2

⭕BC² - BD²= 3AD²

⭕Or, BC² - BD²= 3/4AC² both are correct.

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