Question

9. In a triangle, one angle is 130° and the other two angles are equal. Write the measures
of other two angles of the triangle.​

Answer 1

• Measure of other two angles of triangle are 25° and 25°.

Step-by-step explanation:

To find:-

• Measure of other two angles of triangle.

Solution:-

Given that,

One angle of triangle is 130°.

Let, Other two angles of triangle be x and x.[ We take both angles be x because it is given that, Other two angles of triangle are equal]

We know,

Sum of all interior angles of triangle is equal to 180°.

➝ 130° + x + x = 180°

➝ 130° + 2x = 180°

➝ 2x = 180° - 130°

➝ 2x = 50°

➝ x = 50°/2

➝ x = 25°

Verification:-

➝ 130° + x + x = 180°

• Put x = 25°

➝ 130° + 25° + 25° = 180°

➝ 180° = 180°

Hence, Verified!!.

We have taken other two angles of triangle be x and x. So, Measure of other two angles of triangle is 25° and 25°.

Answer 2

${ \bold { \underline{\large \purple {Required \: Answer : - }}}} \:$

${ \bold { \underline{\large{Given : - }}}} \:$

$one\:angle\:of\:triangle\:=\:130°\:and\:other\:two\:angles\:are\:equal$

${ \bold { \underline{\large{To \: Find : - }}}} \:$

$\tt{Measure\:of\:2\:missing\:angles\:of\:given\:triangle}$

$\large\boxed{\boxed {\tt{ ⇝So\:let's \:do\:it\::-}}}$

$\large\tt\underline{let\:one\:angle\:of\:triangle\:=\:x}$

$\tt{We\:know\:that\:both\:angles\:are\:equal}$

$\tt\therefore{Both\:angles\:=\:x}$

$\large{\pink\star\underline{\tt{So\:let's \:find\:missing\:angles\::-}}}$

$\tt{\red\dag\underbrace{Now\:we\:will\:use\:angle\:sum\:property\:of\:triangle}}\red\dag$

$\tt{sum\:of\:all\:angles\:=\:180°}$

$\tt{130°\:+\:x\:+\:x\:=\:180°}$

$\tt{130°\:+\:2x\:=\:180°}$

$\tt{2x\:=\:180°\:-\:130°}$

$\tt{2x\:=\:50°}$

$\tt{x\:=\:{\dfrac{50°}{2}}}$

$\tt{x\:=\:{\cancel{\dfrac{50°}{2}}}}$

$\boxed{\tt{\therefore{x\:=\:25°}}}$

$\tt \orange {So,\:measure\:of\:both\:missing\:angles\:is\:25°.}$

$\tt{\red\dag\underbrace{verification}}\red\dag$

$\tt{130°\:+\:x\:+\:x\:=\:180°}$

$\tt\pink{we\: know\: x\:=\: 25°}$

$\tt\purple{Let's\: put\: it's \:value}$

$\tt{130°\:+\:25°\:+\:25°\:=\:180°}$

$\tt{130°\:+\:50°\:=\:180°}$

$\tt{180°\:=\:180°}$

$\tt{\pink\star\underbrace{\overbrace{Hence\:verified}}}\purple\dag$

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${ \bold { \underline{\large{Important \: notice : - }}}} \:$

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