Question

9. In AABC, AD I BC. Find the length
of BC.
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Answer 1

Answer:

by using Pythagoras theorm Step-by-step explanation:

b = base

h = hypotenios

p = perpendicular

trialngle ACD

h 2 = b 2 + p2

15 ^2 = B 2 + 12^2

225 = B2 + 144

225 - 144 = DC ^2

81 = DC ^2

9= DC

triangle ABD

h 2 = b 2 + p2

13^2 = B 2 + 12^2

169 = B2 + 144

169- 144 = BD ^2

25 = BD^ 2

5 = BD

BD + DC = BC

5 + 9 = BC

14 = BC

sorry it got deleted all once so it tooked time

i hope it helps