Question

9. In adjacent figure AB = AD,angle BAC = angleCAD. Prove that AC bisects angle BCD​

Answer 1

Step-by-step explanation:

We have ∠1=∠2 and ∠3=∠4

⇒∠1+∠3=∠2+∠4

⇒∠ACD=∠BDC.

Thus in triangles ACD and BDC, we have,

∠ADC=∠BCD (given);

CD = CD (common);

∠ACD=∠BDC (proved).

By ASA condition △ACD≅△BDC. Therefore

AD=BC and ∠A=∠B.

Answer 2

The triangle will be coined to the sides of the mutually perpendicular on itself