9. In an A.P. if the 12th term is - 13 and the sum of its
first four terms is 24, find the sum of its first 10 terms.
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Answer:
the sum of first 10 terms will be zero
explanation
12 th term is -13 that means ,a + 11d = -13 equation ...1
sum of first four terms is 24 ,that mean
Sn = n/2 (2a + (n-1 )d)
24 = 4/2 (2a + (4-1)d)
24 = 2 (2a + 3d )
therefore , 2a +3d =12 equation...2
solving equation 1 and 2 you get d = -2
putting d = -2 in equation 1 ,you get a= 9 .
now sum of first 10 terms will be ,
Sn = n/2 (2a+(n-1 )d)
S10 = 10/2 (2×9 +(10-1)×(-2))
solving this you will get answer zero .
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