Question

9. In an experiment 6.21g of lead combine
with 4.26
g of Chlarine, what is the
empirical formula of
chloride of
of lead
metal
Pb= 207
cl - 35.5

Please send it with full explanation
​

Answer 1

Answer:

Correct option is

D

PbCl

4

Element Mass Atomic weight Relative No. of atoms Simplest ratio

Lead 6.21 g 207 6.21/207 = 0.03 0.03/0.03 = 1

Chlorine 4.26 g 35.5 4.26/35.5 = 0.12 0.12/0.03 = 4

Hence, empirical formula is PbCl

4

.

okkk