Question

9
In case of pure rolling, the velocity of a particle A of
the disc of radius R as shown in figure, is
(1) Vcm
(2) 2Vcm
(3)√3Vcm
(4) 3/2 Vcm
​

Answer 1

Solution:-

:$\implies$ $\sf V_{any\:point}$ = $\sf V_{com}$ + wr

:$\implies$ $\sf V_{p}$ = v + $\sf\dfrac{V}{R}$ × $\sf\dfrac{R}{2}$

:$\implies$ $\sf V_{p}$ = v + $\sf\dfrac{V}{2}$ = $\sf\dfrac{3V}{2}$

hence, option 4 is right.