9. In Fig. 10.13, XY and X'Y' are two parallel tangents to a circle with centre O and
another tangent AB with point of contact C intersecting XY at A and X'Y' at B. Prove
that ZAOB = 90°.
Answers
Answered by
26
Answer:
this is the solution to ur query..hope it helps you..plz mark as brainliest
Attachments:
Answered by
4
• Qᴜᴇꜱᴛɪᴏɴ:
ɪɴ ꜰɪɢ., xʏ ᴀɴᴅ x'ʏ' ᴀʀᴇ ᴛᴡᴏ ᴘᴀʀᴀʟʟᴇʟ ᴛᴀɴɢᴇɴᴛꜱ ᴛᴏ ᴀ ᴄɪʀᴄʟᴇ ᴡɪᴛʜ ᴄᴇɴᴛʀᴇ ᴏ ᴀɴᴅ ᴀɴᴏᴛʜᴇʀ ᴛᴀɴɢᴇɴᴛ ᴀʙ ᴛᴏᴜᴄʜɪɴɢ ᴀᴛ ᴄ, ɪɴᴛᴇʀꜱᴇᴄᴛɪɴɢ xʏ ᴀᴛ ᴀ ᴀɴᴅ x'ʏ' ᴀᴛ ʙ. ᴘʀᴏᴠᴇ ᴛʜᴀᴛ ᴢᴀᴏʙ = 90°.
• ꜱᴏʟᴜᴛɪᴏɴ :
ʟᴇᴛ ᴜꜱ ᴊᴏɪɴ ᴘᴏɪɴᴛ ᴏ ᴛᴏ ᴄ.
ɪɴ ᴀᴏᴘᴀ ᴀɴᴅ ᴀᴏᴄᴀ,
ᴏᴘ = ᴏᴄ (ʀᴀᴅɪɪ ᴏꜰ ᴛʜᴇ ꜱᴀᴍᴇ ᴄɪʀᴄʟᴇ)
ᴀᴘ = ᴀᴄ (ᴛᴀɴɢᴇɴᴛꜱ ꜰʀᴏᴍ ᴘᴏɪɴᴛ ᴀ)
ᴀᴏ = ᴀᴏ (ᴄᴏᴍᴍᴏɴ ꜱɪᴅᴇ)
ᴀᴏᴘᴀ = ᴀᴏᴄᴀ (ꜱꜱꜱ ᴄᴏɴɢʀᴜᴇɴᴄᴇ ᴄʀɪᴛᴇʀɪᴏɴ)
ᴛʜᴇʀᴇꜰᴏʀᴇ, ᴘ ᴄ, ᴀ + ᴀ, ᴏ - ᴏ
ᴢᴘᴏᴀ = ᴢᴄᴏᴀ ... (1)
ꜱɪᴍɪʟᴀʀʟʏ, ᴀᴏQʙ = ᴀᴏᴄʙ
ᴢQᴏʙ = 2ᴄᴏʙ . (ɪɪ) ...
ꜱɪɴᴄᴇ ᴘᴏQ ɪꜱ ᴀ ᴅɪᴀᴍᴇᴛᴇʀ ᴏꜰ ᴛʜᴇ ᴄɪʀᴄʟᴇ, ɪᴛ ɪꜱ ᴀ ꜱᴛʀᴀɪɢʜᴛ ʟɪɴᴇ.
ᴛʜᴇʀᴇꜰᴏʀᴇ, ᴘᴏᴀ + 2ᴄᴏᴀ + ᴄᴏʙ + ᴢQᴏʙ = 180°
ꜰʀᴏᴍ ᴇQᴜᴀᴛɪᴏɴꜱ (ɪ) ᴀɴᴅ (ɪɪ), ɪᴛ ᴄᴀɴ ʙᴇ ᴏʙꜱᴇʀᴠᴇᴅ ᴛʜᴀᴛ
2∠ᴄᴏᴀ+2∠ᴄᴏʙ=180∘
∠ᴄᴏᴀ+∠ᴄᴏʙ=90∘
∠ᴀᴏʙ=90∘
Similar questions