Question

9. In Fig. 10.13. XY and X'Y' are two parallel tangents to a circle with centre o and another tangent AB with point of contact C intersecting XY at A and XY' at B. Prove that ZAOB = 90° ....Tis type same another example
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Answer 1

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Since,POQ is a diameter of the circle, it is a straight line.

Therefore, ∠POA+∠COA+∠COB+∠QOB=180

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So, from equation (1) and equation (2)2∠COA+2∠COB=180

∘∠COA+∠COB=90

∘∠AOB=90

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