9. In fig.if AP|| BQFind.angle BDC. I want will explanation thanx in advance
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Answer:
∠BDC = 65°
Step-by-step explanation:
∠PAB + ∠QBA = 180° [∵ Supplementary angles]
105° + ∠QBA = 180°
∠QBA = 180 - 105
∠QBA = 75°
∠QBA = ∠DBC [∵ Vertically Opposite Angles]
∠DBC = 75°
∠DCB + ∠DBC + ∠BDC = 180° [∵ Angle Sum Property of Triangle = 180°]
∠BDC + 75° + 40° = 180°
∠BDC + 115° = 180°
∠BDC = 180° - 115°
∠BDC = 65°
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i think this is the answer............I hope this helps u
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