Math, asked by rajapandey7843, 1 year ago

9. In . PQ and RS are two mirrors placed
parallel to cach other. An incident ray AB strikes
the mirror PQ at B. the reflected ruy moves along
the path BC and strikes the mirror RS at C and
again reflects back along CD. Prove that
AB II CD.​

Answers

Answered by pratyush7033
1

Answer:

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Answered by CommanderBrainly
1

Answer:

Step-by-step explanation:

PQ || RS ⇒ BL || CM

[∵ BL || PQ and CM || RS]

Now, BL || CM and BC is a transversal.

∴ ∠LBC = ∠MCB …(1) [Alternate interior angles]

Since, angle of incidence = Angle of reflection

∠ABL = ∠LBC and ∠MCB = ∠MCD

⇒ ∠ABL = ∠MCD …(2) [By (1)]

Adding (1) and (2), we get

∠LBC + ∠ABL = ∠MCB + ∠MCD

⇒ ∠ABC = ∠BCD

i. e., a pair of alternate interior angles are equal.

∴ AB || CD.

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