Question

9. In the adjacent figure, ABCD is a parallelogram and line segments AE
and CF bisect the angles A and C respectively. Show that AE || CF.
Hint. In triangles ADE and CBF. we have AD = BC. B =D
and ZDAE - ZBCF
A 20 DAE BCF
ADE CBF. And therefore, CD-DE - AB-BF.
5. CE = AF
AECF is a parallelogram
Hence. AE CF​

Answer 1

Answer:

In triangles ADE and CBF,

we have AD = BC, B =D and Ang. DAE - Ang. BCF

DAE = BCF

ADE = CBF

Therefore,

CD-DE=AB-BF.

CE = AF

AECF is a parallelogram.

Hence. AE || CF