Question

9. In the adjoining figure, ABC is right-angled at B
and A= 30°. If BC =6 cm, find (i) AB, (ii) AC.​

Answer 1

$\LARGE\mathfrak{answer}$

Draw a right angled △ABC using the given instructions :

Here, sin 30 = $\large\frac{BC}{AC}$

$\large\frac{1}{2}$ = $\large\frac{6}{AC}$

Or AC = $\large\rm\orange{12cm}$

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By applying Pythagoras Theorem:

(AB)² = (AC)² - (BC)²

= (12)² - (6)²

= 108

AB = $\large\sf\orange{6}$$\large\sf\sqrt\orange{3}$