9. In the adjoining Figure, ABCD is a parallelogram.
If Z DAB = 85º and Z DBC = 60°, then calculate :
(i) Z CDB
(ii) Z ABD
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Step-by-steFrom the figure we know that ∠OBC = ∠DBC = 60 o. So we get ∠OBC = 60 o. Therefore, ∠OBC = 60 o. 11. In the adjoining figure, chords AC and BD of a circle with centre O, intersect at right angles at E. If ∠OAB = 25 o, calculate ∠EBC. Solution: We know that OA and OB are the radius. Base angles of an isosceles triangle are equal. So we get ∠OBA = ∠OAB = 25 o. Consider OAB. Using the angle sum property ∠OAp explanation:
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