Question

9. In the adjoining, figure, ABCD is a quadrilateral
and AC is one of its diagonals. Prove that
(1) AB+BC +CD+DA>2AC
(1) AB + BC + CD > DA
(li) AB + BC + CD + DA > AC + BD​

Answer 1

Answer:

In ΔABC; AB+BC>AC

Add CD on B.S

AB+BC+CD>AC+CD …….(1)

In ΔACD

AC+CD>AD ………(2)

From (1) & (2)

AB+BC+CD>AD.

Step-by-step explanation:

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