Question

9. In the adjoining figure, the diagonals of a parallelogram
intersect at O. OE is drawn parallel to CB to meet AB at
E, find
area of AAOE : area of Ilgm ABCD.​

Answer 1

Answer:

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I think this sum is in 9th class

Answer 2

Step-by-step explanation:

The diagonals of a parallelogram intersect at O

OE is drawn parallel to CB to meet AB at E .

in the figure four triangles have equal area.

so, area of triangle OAB = 1/4 area of parallelogram ABCD

then, O is the midpoint of AC of triangle ABC and DE||CB

E is also midpoint of AB

therefore, OE is the median of triangle AOB

Area of triangle AOE = 1/2 area of triangle AOB

=1/2×1/4 area of parallelogram ABCD

= 1/8 area of parallelogram ABCD

So, Area of triangle AOE/ area of parallelogram ABCDZ =1/8

Therefore , area of triangle AOE : area of parallelogram ABCD is 1 : 8.