Question

9. In the given fig. AR = 7 cm, AP = 5 cm
PB = 4 cm, RC = 2 cm. The area of
quadrilateral APBC is :
R 2 C
7
B
4
A 5
Р
(A) 20 cm2
(B) 13 = cm
(C) 23 cm
(D) 23 cm
2
23-
11.1​

Answer 1

Answer:

In △OAQ and △OBP, we have

        ∠A=∠B                   [Each equal to 90∘]

       ∠AOQ=∠BOP

So, by AA-criterion of similarity, we have

      △AOQ∼△BOP

⇒  Area(BOP)Area(△AOQ)=OP2OQ2

⇒ 150Area(△AOQ)=5272

⇒ Area(△AOQ)=2549×150cm2=294cm2