Question

9. In the given figure, AB || CD and the bisectors of ✓A and B
meet at P. If ✓C = 70° and ✓D = 50°, find ✓APB. please solve it fast.
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Answer 1

Answer:

∠APB=60°

Step-by-step explanation:

∠CDA+∠DAB=180°[Co interior angles on same side of tranasversal]

50°+∠DAB=180°

∠DAB=180°-50°=130°

∠DAP=∠PAB=1/2(∠DAB)

       = 1/2(130°)

       =65°

∠ACB+∠CBA=180°[Co interior angles on same side of tranasversal]

70°+∠CBA=180°

∠CBA=180°-70°=110°

∠PBA=∠PBC=1/2(∠CBA)

                =1/2(110°)

               =55°

∠PAB+∠PBA+∠APB=180°[Angle sum property of triangle]

65°+55°+∠APB=180°

120°+∠APB=180°

∠APB=180°-120°=60°

Answer 2

Answer:

Angle APB is 60 degree .