Question

9.
In the given figure, line RT is drawn parallel
to SQ. If QPS = 100°, PQS = 40°,
PSR = 85º and QRS = 70°, then
QRT =
(A) 45° (B) 65° (C) 85°
90°​

Answer 1

• gghjj and I am not sure if you have any questions or need any further information please contact me at
• use of an object to this email is strictly prohibited from using copying altering and the yyyyyyyyyyyyyyyyyyyyyyyyyyyyyyy the r lfor for a few of them in my hhhhhjjjjjjjj the use of the yyyyyyyyyyyyyyyyyyyyyyyyyyyyyyy the r lfor the use of the yyyyyyyyyyyyyyyyyyyyyyyyyyyyyyy the r lfor the use you have any questions or need any further information pl me at the end of the yyyyyyyyyyyyyyyyyyyyyyyyyyyyyyy the r lfor the

Answer 2

Answer:

From the figure

In △PQS,

∠PQS+∠QPS+∠PSQ=180  

∘

 

⟹∠PSQ=180  

∘

−∠QPS−∠PQS=180  

∘

−100  

∘

−40  

∘

=40  

∘

 

Given ∠PSR=85  

∘

⟹∠PSQ+∠QSR=85  

∘

⟹∠QSR=85  

∘

−∠PSQ=85  

∘

−40  

∘

=45  

∘

 

In △QSR

∠QRS+∠PSQ+∠SQR=180  

∘

 

∠SQR=180  

∘

−∠QRS−∠QSR=180  

∘

−70  

∘

−45  

∘

=65  

∘

 

AS RT∥SQ

∠QRT=∠SQR=65  

∘

                      (∵alternative angles)

: