Question

9. In the given figure, triangles ABC and DCB are right-
angled at A and D respectively and AC-DB.
Prove that AABC = ADCB.​

Answer 1

Answer:

It is a figure of square with diagonal CB

==>So it forms 2 triangles ABC & DBC

Given = angle A = angle D=90°

AC=DB

Proof =

In ∆ABC & ∆DBC

<A = <D ( Given )

AC = DB ( Given )

CB = CB ( Comman side )

So by SAS rule of congurence

∆ ABC= ∆DBC