Question

9. In the given triangle, calculate theta if angleB = 90°,
AB = 20 cm and AC = 40 cm.
(ICSE)​

Answer 1

Given information: In triangle ABC, b = 90° AB = 20 cm and AC = 40 cm. =

We need to find the value of e.

Hypotenuse = AC = 40 cm =

Opposite side = AB = 20 cm

In a triangle angle triangle

$sin \: 0 = \frac{opposite}{hypotenuse } \\ sin \: 0 = \frac{20}{40} \\ = > sin \: 0 = \frac{1}{2}$

sin 0 = sin(30°)

On comparing both sides we get

0 = 30°

Therefore, the value of 0 is 30°.

Answer 2

Answer:

Given information: In triangle ABC, b = 90° AB = 20 cm and AC = 40 cm. =

We need to find the value of e.

Hypotenuse = AC = 40 cm =

Opposite side = AB = 20 cm

In a triangle angle triangle

\begin{lgathered}sin \: 0 = \frac{opposite}{hypotenuse } \\ sin \: 0 = \frac{20}{40} \\ = > sin \: 0 = \frac{1}{2}\end{lgathered}sin0=hypotenuseoppositesin0=4020=>sin0=21

sin 0 = sin(30°)

On comparing both sides we get

0 = 30°

Therefore, the value of 0 is 30°.