Question

9. In trapezium ABCD, seg AB||seg BC
seg BN perpendicular to the seg DC
AD =10.BC13.
DM=6 DC = 28
then find A(quadrilateral ABCD)​

Answer 1

Step-by-step explanation:

we can find out the area of triangle ADB

so height for this triangle wud be equal to the height of trapezium.

so we get height = 12cm.

now we can easily get to CD=7cm

and we know area of trapezium =1/2*(AB+CD)*HEIGHT

NOW,1/2*(25+7)*12 = 192 cm.

how to get CD=7 cm

when we will drop two perpendicular lines from D to AB as point E and from C to AB as point F.

So,we can see that EF = CD (as the line drawns were perpendicular)

Now In triangleADE,

We know AD=15 and DE=12

So we can easily find AE = 9

Similarly from triangleBCF,

we will get BF = 9cm

therefore,EF = AB -(AE+BF) = 25 - 18 =7cm.

Hope it Helps.:)