Math, asked by diyagangwani7493, 1 year ago

9 kg of rice cost as much as 4kg of sugar; 14 kg of sugar cost at much as1.5kg of tea; 2 kg of a tea cost as much as 5kg of coffee; find the cost of 11 kg of coffee, if 2.5 kg of rice cost rs12.50?

Answers

Answered by ishubhattvs6
5

Answer:


Step-by-step explanation:


Attachments:
Answered by GulabLachman
4

The cost of 11 kg of coffee is Rs 462.

Let price of 1 kg of rice be Rs r, price of 1 kg of sugar be Rs s, price of 1 kg of tea be Rs t and price of 1 kg of coffee be Rs c.

Given that, 9 kg of rice cost as much as 4kg of sugar. We can represent this as:

9r = 4s

⇒s = (9/4)r                               ...(1)

Also, 14 kg of sugar cost at much as1.5kg of tea. So,

14s = 1.5t

⇒28s  = 3t                      [Multiplying by 2 on both sides]

⇒t = (28/3)s                               ...(2)

Again, 2 kg of a tea cost as much as 5kg of coffee. So,

2t = 5c.

⇒ c = (2/5)t                               ...(3)

Given that 2.5 kg rice costs Rs 12.50

So, 2.5r = 12.50

⇒ r = 12.50/2.5 = 5

So, rice costs Rs 5 per kg.

Putting this value of r in (1), we get

s = (9/4) × 5 = Rs 11.25

Sugar costs Rs 11.25 per kg.

Putting this value of s in (2), we get

t = (28/3) × 11.25 = Rs 105

Tea costs Rs105 per kg.

Putting this value of t in (3), we get

c = (2/5) × 105 = Rs 42

Coffee costs Rs 42 per kg,

Cost of 11 kg of coffee = Rs (42 × 11) = Rs 462

Similar questions