9 kg of rice cost as much as 4kg of sugar; 14 kg of sugar cost at much as1.5kg of tea; 2 kg of a tea cost as much as 5kg of coffee; find the cost of 11 kg of coffee, if 2.5 kg of rice cost rs12.50?
Answers
Answer:
Step-by-step explanation:
The cost of 11 kg of coffee is Rs 462.
Let price of 1 kg of rice be Rs r, price of 1 kg of sugar be Rs s, price of 1 kg of tea be Rs t and price of 1 kg of coffee be Rs c.
Given that, 9 kg of rice cost as much as 4kg of sugar. We can represent this as:
9r = 4s
⇒s = (9/4)r ...(1)
Also, 14 kg of sugar cost at much as1.5kg of tea. So,
14s = 1.5t
⇒28s = 3t [Multiplying by 2 on both sides]
⇒t = (28/3)s ...(2)
Again, 2 kg of a tea cost as much as 5kg of coffee. So,
2t = 5c.
⇒ c = (2/5)t ...(3)
Given that 2.5 kg rice costs Rs 12.50
So, 2.5r = 12.50
⇒ r = 12.50/2.5 = 5
So, rice costs Rs 5 per kg.
Putting this value of r in (1), we get
s = (9/4) × 5 = Rs 11.25
Sugar costs Rs 11.25 per kg.
Putting this value of s in (2), we get
t = (28/3) × 11.25 = Rs 105
Tea costs Rs105 per kg.
Putting this value of t in (3), we get
c = (2/5) × 105 = Rs 42
Coffee costs Rs 42 per kg,
Cost of 11 kg of coffee = Rs (42 × 11) = Rs 462