Question

9.
Least value of expression
(16 sec^2 x - 32 sec+ x +41)/tan^2x
wherever defined is

(A) 20
(C) 200
(B) 40
(D) 400​

Answer 1

Answer:

C 400

Step-by-step explanation:

Multiply both sides by cos2x

So we get,

3sin2x−1−5cos2x=2sin2x−6cos2x=0

So,

2sin2x=6cos2x

tan2x=3

tanx=√3

x=π3