Question

9. Let l be the lower class limit of a class interval in a frequency distribution and m be the mid point of the class. Then the upper class limit of the class is

Answer 1

let a be lower class limit , l is the upper class limit and M is the midpoint .

Step-by-step explanation:

mid point m = a + l / 2

a = 2m -1

hope it helps you ...

Answer 2

Answer:

$\huge\underbrace\mathcal\purple{ANSWER}$...

Let a be lower class limit, l is the upper class limit and m is the mid-point

then, mid-point m= a+1/2

Therefore, a=2m−l