Question

9. lfa + 1/a = 1/(√3- 1),then the value of a ^ 2 + 1/(a ^ 2) is

$a + \frac{1}{a} = \frac{1}{ \sqrt{3} - 1} \: \: then \: the \: value \: of \: {a}^{2} + \frac{1}{ {a}^{2} } is$
(a)3
(b)2√3
(c)-1+√3/2
(d)4√3​

Answer 1

Step-by-step explanation:

$a + \frac{1}{a} = \ \frac{1}{ \sqrt{3} - 1 } \\ by \: squaring \: on \: both \: sides \\ {a}^{2} + \frac{1}{a {}^{2} } + 2 = \frac{1}{3 + 1 - 2 \sqrt{3} } \\ a {}^{2} + \frac{1}{ {a}^{2} } = \frac{1}{4 - 2 \sqrt{3} } - 2 \\ { a}^{2} + \frac{1}{a {}^{2} } = \frac{4 \sqrt{3} - 7 }{4 - 2 \sqrt{3} }$

Answer 2

Answer:

Option C) -1+√3/2

is the correct answer

Refer To The Attachments

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Answer 3

Answer:

Option C) -1+√3/2

is the correct answer

Refer To The Attachment

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Answer 4

Answer:

Option C) -1+√3/2

is the correct answer

Refer To The Attachment

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