Question

9 men and 12 women working 7 hours a day,complete three fourth of a job in 4 days and the remaining part of the job is done by 22 men and 7 women in 2 days working 5 hours a day in how many days for the entire job be done by 6 men and 4 women working 8 hours a day

Answer 1

This is the answer of your question

Answer 2

Answer:

11 days

Step-by-step explanation:

# Three fourth of job done by 9 men and 12 women working 7 hours a day in 4 days.

Number of hours work by men = 9 x 7 = 63 hours

Number of hours work by women = 12 x 7 = 84 hours

Total number of hours work in 1 day = 63 + 84 = 147 hours.

Total work in 4 days = 147 x 4 = 588 hours.

#  The remaining part (one-fourth) of the job is done by 22 men and 7 women in 2 days working 5 hours a day.

Number of hours work by men = 22 x 5 = 110 hours

Number of hours work by women = 7 x 5 = 35 hours

Total number of hours work in 1 day = 145  hours

Total work in 2 days = 290 hours

This is one forth of total work.

# Total work finished = 588 + 290 = 878 hours

#  The entire job be done by 6 men and 4 women working 8 hours a day

Total work done by 6 men and 4 women in 1 day = (6+4)x8 = 80 hours

Let they finish 878 hours work in d days.

$d=\dfrac{878}{80}$

$d\approx 11\text{ days}$

Hence, In 11 days , 6 men and 4 women working 8 hours a day will done entire job.