9 men and 12 women, working 7 hrs a day, complete ths of a job in 4
days and the remaining part of the job is done by 12 men and 7 women in 2
days working 5 hours a day. In how many days would the entire job be done
by 6 men and 14 women working 8 hours a day?
Answers
Answer:
Three fourth of job done by 9 men and 12 women working 7 hours a day in 4 days. Total number of hours work in 1 day = 63 + 84 = 147 hours. Total work in 4 days = 147 x 4 = 588 hours.
Answer:
11 days
Step-by-step explanation:
# Three fourth of job done by 9 men and 12 women working 7 hours a day in 4 days.
Number of hours work by men = 9 x 7 = 63 hours
Number of hours work by women = 12 x 7 = 84 hours
Total number of hours work in 1 day = 63 + 84 = 147 hours.
Total work in 4 days = 147 x 4 = 588 hours.
# The remaining part (one-fourth) of the job is done by 22 men and 7 women in 2 days working 5 hours a day.
Number of hours work by men = 22 x 5 = 110 hours
Number of hours work by women = 7 x 5 = 35 hours
Total number of hours work in 1 day = 145 hours
Total work in 2 days = 290 hours
This is one forth of total work.
# Total work finished = 588 + 290 = 878 hours
# The entire job be done by 6 men and 4 women working 8 hours a day
Total work done by 6 men and 4 women in 1 day = (6+4)x8 = 80 hours
Let they finish 878 hours work in d days.
d=\dfrac{878}{80}d=80878
d\approx 11\text{ days}d≈11 days
Hence, In 11 days , 6 men and 4 women working 8 hours a day will done entire job.
Step-by-step explanation:
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