Math, asked by ganeshmalu27, 6 months ago

9. Mike has a rectangular garden of length 15 m and breadth 10 m. Her friend Adam has a square
garden of side 12 m. whose garden is bigger and by how much?​

Answers

Answered by aditya41859
4

Answer:

Let the length of the diagonal of the square =x m

Then,

2

1

×x×x=12×5

⇒x

2

=120m

2

⇒x=2

30

m.

Answered by purva2143
2

Answer:

Mike's garden is bigger than Adam's garden by 6m.

Step-by-step explanation:

Mike's garden:

shape- rectangle

length of the garden = 15m

breadth of the garden = 10m

So Area of garden = Area of the rectangle

= length × breadth

= 15 × 10

= 150 m

Therefore, Area of Mike's garden is 150 m

Adam's garden:

shape- square

length of the side of the garden = 12m

So Area of garden = Area of the square

= side× side

= 12× 12

= 144 m

Therefore, Area of Adam's garden is 144 m

By comparing the gardens of Mike and Adam,

150m > 144m

The area of Mike's garden is bigger than the area of Adam's garden.

150m - 144m = 6m

The difference between the area of their gardens is 6m.

Hence, Mike's garden is bigger than Adam's garden by 6m.

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