Math, asked by pritilatapradhan68, 7 months ago


9. My younger brother's present age is 3 times what it will be 3 years from now minus 3
times what his age was 3 years ago. Find his present age.
10. In a bag, the number of one rupee coins is three times the number of two rupees coin if the worth of the coin is rupees 180 find the number of each type of coin.

Answers

Answered by ItsUDIT
33

Step-by-step explanation:

Let my younger brother be x years old at present.

After 3 years, his age =(x+3)

Before 3 years, her age was =(x−3)

ACCORDING TO QUESTION

x=3(x+3)−3(x−3)

⇒ x=3(x+3−x+3)

⇒ x=2×6

⇒ 18

Therefore, 18 years is the present age of my younger

2. the number of .coin = 1 rupees = x 25 paise coin = x 50 paise coin = x according to question number of coin x /2x / 4x / 7x = 175

x = 57=251757=25

 Value of total amount = 3x = 25×3= Rs.7525×3 = Rs.75

Answered by Anonymous
1

Answer:

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