9^n-1 is multiple of 8
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So for any given n which is a product of eight, n+1 would meet it, n+3, n+5, n+7,as well and n+2, n+4, n+6 would not. There are 77 possible n's, of which 39 are odd and would meet the criteria and 9 are multiples of 8 so the total would be 48.
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Answer:
So for any given n which is a product of eight, n+1 would meet it, n+3, n+5, n+7,as well and n+2, n+4, n+6 would not. There are 77 possible n's, of which 39 are odd and would meet the criteria and 9 are multiples of 8 so the total would be 48. k=n(n+1)(n+2) as a multiple of 8.
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