9 number koi solve kar do yaar
Answers
Step-by-step explanation:
The renquired points which are
equidistant from the given points and lie on x-axis are (5,0)and(17,0)
Given :-
Given point A(11,-8) and Distance is 10 units
To find:-
Find the points on the x-axis which is at equidistant from A
Solution:-
Let the required point which is on the x-axis be (x,0)
since the equation of x-axis is y=0
And given point is A(11,-8)
Using formula:-
If(x1,y1) and (x2,y2) are the points then the distance between them is
√[(x2-x1)²+(y2-y1)²] units
now
we have (x1,y1)=(11,-8)=>x1=11;y1=-8
and (x2,y2)=(x,0)=>x2=x;y2=0
Distance between the given points=10 units
=>√[(x-11)²+{(0-(-8)}²=10
=>√[(x-11)²+8²]=10
=>√[x²-2(x)(11)+(11)²+8²]=10
=>√[x²-22x+121+64]=10
=>√[x²-22x+185]=10
on squaring both sides
=>{√[x²-22x+185]}²=10²
=>x²-22x+185=100
=>x²-22x+185-100=0
=>x²-22x+85=0
=>x²-5x-17x+85=0
=>x(x-5)-17(x-5)=0
=>(x-5)(x-17)=0
=>x-5=0 or x-17=0
x=5 and x=17
Answer:-
The renquired points which are equidistant from the given points and lie on x-axis are (5,0) and (17,0)