Question

9. Obtain a value for the pressure due to a liquid
of density d, acceleration due to gravity g at a depth of h cm below its surface. ​

Answer 1

Explanation:

Pressure due to the weight of a liquid of constant density is given by p=ρgh p = ρ g h , where p is the pressure, h is the depth of the liquid, ρ is the density of the liquid, and g is the acceleration due to gravity.

Answer 2

Answer:

All the liquids exert pressure on the base or bottom and walls of their container. All the liquid have weight. ... The pressure exerted by a liquid increases with increasing depth inside the liquid. The pressure exerted by a liquid is small just under the surface of the liquid.