Math, asked by drmanishaawasthi28, 11 months ago

9 On a certain sum of money, invested at the rate of > Por
annually, the difference between the interest of the first year and the inte
interest of the first year and the interest of the third
year is 61.50. Find the sum​

Answers

Answered by aditya409115
2

Answer:

et the sum (Principle) = Rs. 100

C.I. of 1st year = Rs. \frac{100\times 5\times 1}{100} = Rs. 5</span><span>And,amountof1styear=Rs.100+Rs.5=Rs.105

⇒ The principke for 2nd year = Rs. 105

C.I. of 2nd year =Rs.  

100

105×5×1

​  

=Rs.5.25

And, amount of 2nd year =Rs.105+Rs.5.25=Rs.110.25

⇒ The principle for 3rd year =Rs.110.25

C.I. of 3rd year =Rs.  

100

110×5×1

​  

=Rs.5.5125

Difference between C.L of 1st year and C.L of 3rd year =Rs.5.5125−Rs.5=Rs.0.5125

Now, when the difference of interest =Rs.0.5125,sum=Rs.100

And, when the difference of interest =Rs.61.50,sum=Rs.  

0.5125

100

​  

×61.50=Rs.12,000 (Ans)

Step-by-step explanation:

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