9 p square minus 100
Find the zeros and the relationship between zeros and the cofficient
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9p^2 -100 = 0
(3p)^2 - (10)^2 = 0
(3p+10)(3p-10)=0
( by identity (a^2 - b^2) )
p= 10/3 or p = -10/3
relationship between zeroes and coefficients ---
sum of zeroes = - coefficient of x/coefficient x^2
10/3 - 10/3 = 0/9
0=0
product of zeroes = c/a
= -100/9 = -100/9
HENCE PROVED
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Answer:
Step-by-step explanation:
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