Question

9)
P(x) = x2 – 3x + 2. find p (1), p(2), P(-1) and
P(-2)​

Answer 1

Answer:

Given polynomial is p(x)=x

2

−3x+2

Replace x by 0, we get

p(0)=(0)

2

−3(0)+2

⇒p(0)=0+0+2

⇒p(0)=2

Replace x by 1, we get

p(1)=(1)

2

−3(1)+2

⇒p(1)=1−3+2

⇒p(1)=0

Replace x by 2, we get

p(2)=(2)

2

−3(2)+2

⇒p(2)=4−6+2

⇒p(2)=0

Answer 2

Step-by-step explanation:

p (1)=1

p (2)=0

p (-1)=3

p (-2)=4

In -1 and -2 we know that while simplifying

identify the symbols

-×-=+

-×+=-

+×-=-

+×+=+