Math, asked by joshipratyaksh08, 18 days ago

9 people went a hotel for dinner. 8 of them spent ruppes 60 each and the ninth person spent 40 more than the average of the money spent by 9. What was the total expedenture. Let's see who can solve this.​

Answers

Answered by vanshjainhero2007
1

Answer:

520

Step-by-step explanation:

8*60+40=520

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Answered by pradiptadas2007
5

Answer:

The total expenditure was ₹585.

Step-by-step explanation:

8 people spent ₹60 each.

Let money spent by 9th person be ₹x

So, their avg.= ₹(60×8+x)/9 = ₹(480+x)/9.

Given that,

9th person spent ₹40 more than avg. of them 9 people

Hence, (480+x)/9 +40 = x

or, (480+x)/9 = x-40

or, 480+x = (x-40)×9

or, 480+x = 9x-360

or, x-9x = -360-480

or, -8x = -840

or, x = -840/-8

or, x = 105

So, 9th person spent ₹105

Total money spent by them = ₹(60×8+105) = ₹585.

Therefore, the total expenditure was ₹585.

Hope it helps you...

Pls mrk me brainliest...

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