Question

9. Perpendiculars AL, BM are drawn from the
vertices A, B of a triangle ABC to meet BC, AC
at L, M. By proving the triangles ALC, BMC
similar, or otherwise, prove that
CM.CA = CL.CB.


please answer this, it's very very urgent​

Answer 1

Step-by-step explanation:

Perpendiculars al and bm are drawn from the vertices a and b of triangle abc to meet bc and acat l and m respevtively . ... In △ CMB and △ CLA ∠ CMB = ∠ CLA Each 90 ° , as BM and AL are perpendiculars ∠ MCB = ∠ LCA Same angle By AA similarity criterion △ CMB ~ △ CLA So , CM CL = CB CA CM × CA = CL × CB Hence Proved .