Question

9 pipes are required to fill a tank in 4 hours.how long will it take if 12 pipes of the same type are used​

Answer 1

Answer:

Correct option is

D

96 min

6 pipes = 80 mins

5 pipes = x

6×80 = 5×x

56×80 = x

6×16 = x

x = 96

Answer 2

12 pipes of the same type are required to fill a tank in 5 hours 20 min.

Given: 9 pipes are required to fill a tank in 4 hours.

To Find: The time required by 12 pipes of the same type to fill the tank.

Solution:

• We shall solve the numerical by implementing the concept of the unitary method.

• In the unitary method, the value to be found must always be kept on the right-hand side.

Coming to the numerical, we are given;

9 pipes are required to fill a tank in = 4 hours

So, 1 pipe is required to fill a tank in = ( 4 / 9 ) hours

So, 12 pipes are required to fill a tank in = (( 4 × 12 ) / 9 ) hours

                                                                   = 5 hours 20 min

Hence, 12 pipes of the same type are required to fill a tank in 5 hours 20 min.

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