Math, asked by gauravgupta11110262, 6 months ago

9. Prove that each of the following numbers is irrational.
(vi)2/√5​

Answers

Answered by khushigupta90
0

Answer:

Let √6 = √2 × √3 be rational. Hence, √2, √3 are both rational. This contradicts the fact that√2, √3 are irrational. The contradiction arises by assuming √6 is rational. Hence, √6 is irrational.Read more on Sarthaks.com - https://www.sarthaks.com/127076/prove-that-each-of-the-following-numbers-is-irrational-6

Answered by jayesh321
0

Answer:

We need to prove√2+√5 is an irrational number. Let us assume that √2+√5 is a rational number. p,q are integers then (p²-7q²)/2q is a rational number. ... √2+√5 is an irrational number.

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