9) q An tirangle ABC, is AB=15° and B-C=30, then angles A, B, C are
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Answer:
sum of angles is =180 °
AB= 15°
BC= 30°
AC= ?
So,AC is x
15+30+x= 180°
45+x= 180°
x= 180°-45°
Therefore angleAC =135°
SO,AB+BC+AC= 180°
15°+10°+135°=180°
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