Physics, asked by debashispanda199, 25 days ago

9.Ravi jogs from one end A to the other end B of a straight 250 m road in 1min and 40 s. He
then turns around and jogs50 m back to a point C in 30 s. Calculate average speed and
average velocity in jogging from (a) A to B (ii) A to C

Answers

Answered by raelul
3

Answer:

(a) Average speed = Total distance covered / Total time taken

= 250m + 50m / 1 min 40 s + 30 s

= 300m / 130 s

= 30/13

= 2.3 m/s

(b) Average velocity = Total displacement / Total time taken

= 200 m / 130 s

= 1.5 m/s

Answered by abhishek234565
0

Answer:

a) Average speed = Total distance covered / Total time taken

= 250m + 50m / 1 min 40 s + 30 s

= 300m / 130 s

= 30/13

= 2.3 m/s

(b) Average velocity = Total displacement / Total time taken

= 200 m / 130 s

= 1.5 m/s

Explanation:

a) Average speed = Total distance covered / Total time taken

= 250m + 50m / 1 min 40 s + 30 s

= 300m / 130 s

= 30/13

= 2.3 m/s

(b) Average velocity = Total displacement / Total time taken

= 200 m / 130 s

= 1.5 m/s

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