Question

9. Renuka walked 12 m towards east. Then she turned to the right and walked 3 m. Again she turned to the right and walked 16m.How far is she from the starting point? O 10km 0 5km O 12km with OS​

Answer 1

suppose starting point is A, 12m towards east this is B then she turned 3m south or right this point is C again she turned right or west this point is DC-AB=3m .DAF=Right angle triangle hence line segment DF= Base-(b) AF= perpendicular (p) DA= height- (h).

b= 4cm, p= 3cm. h= √4²+3²=√16+9=√25=5 .

The answer is 5m.

Answer 2

The answer is 5 cm

GIVEN

Renuka walked 12 m towards east. Then she turned to the right and walked 3 m. Again she turned to the right and walked 16m.

TO FIND

How far is she from the starting point?

SOLUTION

We can simply solve the above problem as follows;

Let the starting point be 'O'.

Distance towards East, OA = 12 meters

Distance towards North, AB = 3 meters

Distance towards West, BC = 16 meters

Distance between Starting point and Final point = CO

Let us extend Point 'O' to P

Such that,

OP = AB = 3 meters

And,

OA = BP = 12 meters

PC = 16-12 = 4 meters

In ΔPCO

Applying pythagorus theorem in ΔPCO

CO² = PC² +PO²

= 3² + 4²

= 9 + 16

CO² = 25

CO = √25 = 5 cm

Hence, The answer is 5 cm

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