Question

9) Ride number one is the fastest roller coaster at the park. To get over the initial hill, riders blast off from the start. Riders go from 0 – 55 m/s in 15 s. What is the acceleration?

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Acceleration=3.67\:m/s^{2}}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Initial \: velocity (u)= 0 \: m/s \\ \\ \tt: \implies Final \: velocity (v)= 55 \: m/s \\ \\ \tt: \implies Time(t) = 15 \: sec \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Acceleration(a) =$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies v = u + at \\ \\ \tt: \implies 55 = 0 + a \times 15 \\ \\ \tt: \implies 55 = a \times 15 \\ \\ \tt: \implies a = \frac{55}{15} \\ \\ \green{\tt: \implies a = 3.67 { \: m/s}^{2} } \\ \\ \green{\tt \therefore Acceleration \: of \: roller \:coaster \: is \: 3.67 \: {m/s}^{2} }\\\\ \blue{ \bold{Some \: related \: formula}} \\ \orange{\tt \circ \: s = ut + \frac{1}{2}at^{2}} \\ \\ \orange{\tt \circ \: {v}^{2} = {u}^{2} + 2as}$

Answer 2

Answer:

For showing Full answer click on photo.