9 संख्या 763x4y2 यदि 9 से पूर्ण विभाजित है, तो x औरy के कितने जोडे संभव है? 2 (a)8 (b)9 (c) 10 (d) 11 w
Answers
Answered by
1
Answer:
5
Step-by-step explanation:
To be divisible by 9.
7 + 6 + 3 + x + 4 + y + 2 = 27
22 + x + y = 27
x + y = 5
Hope it helps.
Answered by
1
Answer:
5
Step-by-step explanation:
7+6+3+x+4+y+2=27
22+x+y= 27
- x+y=5
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