Math, asked by db2412272, 16 hours ago

9 संख्या 763x4y2 यदि 9 से पूर्ण विभाजित है, तो x औरy के कितने जोडे संभव है? 2 (a)8 (b)9 (c) 10 (d) 11 w​

Answers

Answered by TigerMan28
1

Answer:

5

Step-by-step explanation:

To be divisible by 9.

7 + 6 + 3 + x + 4 + y + 2 = 27

22 + x + y = 27

x + y = 5

Hope it helps.

Answered by saylimargi333
1

Answer:

5

Step-by-step explanation:

7+6+3+x+4+y+2=27

22+x+y= 27

  • x+y=5
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