Question

9 sec^2 A - 9 tan^2 A =?????

Answer 1

Step-by-step explanation:

= 9(sec²2A-tan²2A)

= 9*1

=9

Answer 2

$\huge\mathcal\pink\{QUESTION}$

$9 { \sec( \alpha ) }^{2} - 9{ \tan( \alpha ) }^{2}$

$\huge\mathbb\purple\{ANSWER}$

FIRST OF ALL WE TAKE 9 AS COMMON.

$9( { \sec( \alpha ) }^{2} - { \tan( \alpha ) )}^{2}$

NOW, we know the trigonometry identity.

$\red\{</p><p>[tex]1 + { \tan( \alpha ) }^{2} = { \sec( \alpha ) }^{2}$

$so$

${ \sec( \alpha ) }^{2} - { \tan( \alpha ) }^{2} = 1}$

so, by using this identity

$9 \times 1$

$9$

$\huge\mathcal\green\{SO FINAL ANSWER}$

9