Question

9 sec^2 A-9 tan^2A-​

Answer 1

Step-by-step explanation:

9sec^2A-9tan^2A

=9(sec^2A-tan^2A)

=9(1÷cos^2A-sin^A÷cos^2A)

=9(1-sin^2A÷cos^2A)

=9(cos^2A÷cos^2A)

=9×1

=9

Answer 2

Answer:

the answer is 9

Step-by-step explanation:

9 sec²A- 9tan²A

= 9( $\frac{1}{cos^2 A}$- $\frac{sin^2 A}{cos^2 A}$ )

=9($\frac{1-sin^2A}{cos^2 A}$)

=9($\frac{cos^2 A }{cos^2 A}$)

=9×1

=9