Question

9 sec ²A-9 tan ²A.........​

Answer 1

Answer:

sec^A-tan^A = 1

so 9sec^A - tan^A

= 9(sec^A - tan^A)

=9*1

=9

Step-by-step explanation:

hope it helps you

Answer 2

Answer:

${ \sec }^{2} a - { \tan}^{2} a = 1$

so;

if u take 9 as common u get.

=9×1

=9.

hope it helps u dii.