Math, asked by krishan427384kk, 10 months ago

9 sec^2A-9tan^2A solve it​

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Answered by ankitsaini76216
4

Answer:

 9 {sec}^{2} a - 9 {tan}^{2}   \\  =  9( {sec}^{2}a -  {tan}^{2}  ) \\ = 9(1 +  {tan}^{2} a -  {tan}^{2} a) \\ =  9 \times (1) \\  = 9

I hope this help you

Answered by Anonymous
3

Answer:

9 { \sec }^{2} a - 9 {tan}^{2} a \\  = 9( {sec}^{2} a -  {tan}^{2}a ) \\  = 9(1)  \:  \:  \:  \:  \:  \:  \: (  {sec}^{2} -  {tan}^{2}  = 1 ) \\  = 9

Hope it helps you.

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