Question

9 sec^2A-9tan^2A solve it​

Answer 1

Answer:

$9 {sec}^{2} a - 9 {tan}^{2} \\ = 9( {sec}^{2}a - {tan}^{2} ) \\ = 9(1 + {tan}^{2} a - {tan}^{2} a) \\ = 9 \times (1) \\ = 9$

I hope this help you

Answer 2

Answer:

$9 { \sec }^{2} a - 9 {tan}^{2} a \\ = 9( {sec}^{2} a - {tan}^{2}a ) \\ = 9(1) \: \: \: \: \: \: \: ( {sec}^{2} - {tan}^{2} = 1 ) \\ = 9$

Hope it helps you.

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