Question

9 sec a-9tan a बराबर है ​

Answer 1

Step-by-step explanation:

We have, 9sec

2

A−9tan

2

A

Let r=9sec

2

A−9tan

2

A

r=9(sec

2

A−tan

2

A)

We know that

sec

2

A−tan

2

A=1

Therefore,

r=9×1=9

Hence, this is the answer.

Answer 2

Answer:

$9 \sec(a) - 9 \tan(a) \\ : \to \: 9 \times \frac{1}{ \cos(a) } \: \: \: - \: \: 9 \times \frac{ \sin(a) }{ \cos(a) } \\ : \to \frac{9(1 - \sin(a)) }{ \cos(a) }$